Storing cricketer information using STRUCTURE

Question: Define a structure called “Cricket” that will describe the following information: player name, team name and batting average. Using the structure, declare an array player with 50 elements and write a program to read the information about all the 50 players and print a team-wise list containing names of players with their batting average.

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Source Code:

#include <bits/stdc++.h>

struct Cricket{

char playername[100];

char teamname[25];

float average;

}player[51];

int main()

{

    int i,j,n,p;

    char tempteam[25],tempplayer[100];

    float tempaverage;

    printf(“How many informations of players you want to give as input? “);

    scanf(“%d”,&n);

    printf(“Enter %dnPlayer NamenTeam NamenBatting Averagenin three different lines.nn”,n);

    for(i=1;i<=n;i++)

    {

        scanf(“n”,&p);

        gets(player[i].playername);

        gets(player[i].teamname);

        scanf(“%f”,&player[i].average);

    }

    for(i=1;i<=n-1;i++)

    {

        for(j=1;j<=n-i;j++)

        {

            if(strcmp(player[j].teamname,player[j+1].teamname)>0)

            {

                strcpy(tempteam,player[j].teamname);

                strcpy(player[j].teamname,player[j+1].teamname);

                strcpy(player[j+1].teamname,tempteam);

                strcpy(tempplayer,player[j].playername);

                strcpy(player[j].playername,player[j+1].playername);

                strcpy(player[j+1].playername,tempplayer);

                tempaverage=player[j].average;

                player[j].average=player[j+1].average;

                player[j+1].average=tempaverage;

            }

        }

    }

    strcpy(tempteam,player[1].teamname);

    printf(“Team Name: %sn”,tempteam);

    printf(“tPlayer NametBatting averagen”);

    for(i=1;i<=n;i++)

    {

        if(strcmp(tempteam,player[i].teamname)!=0)

        {

            strcpy(tempteam,player[i].teamname);

            printf(“Team Name: %sn”,tempteam);

            printf(“tPlayer NametBatting averagen”);

        }

        printf(“t%10st%15.2fn”,player[i].playername,player[i].average);

    }

    return 0;

}

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